The reaction sequence is as follows:1,4-dibro | vedclass

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(C) Step $1$: $1,4-dibromocyclohex-2-ene$ reacts with $2 \, molar \, equivalents$ of dimethylamine $(CH_3)_2NH$ via $S_N2$ substitution to form $1,4-b

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Benzene

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(C) Step $1$: $1,4-dibromocyclohex-2-ene$ reacts with $2 \, molar \, equivalents$ of dimethylamine $(CH_3)_2NH$ via $S_N2$ substitution to form $1,4-bis(dimethylamino)cyclohex-2-ene$ $(A)$.Step $2$: Treatment with $BaO$ (a base) does not significantly alter the structure in this context,or it acts as a mild base to ensure the amine is free.Step $3$: Reaction with $2 \, molar \, equivalents$ of $CH_3I$ performs exhaustive methylation of the two tertiary amine groups to form a bis-quaternary ammonium salt $(C)$.Step $4$: Treatment with $Ag_2O / H_2O$ (Hofmann elimination conditions) leads to the elimination of the two trimethylamine groups,resulting in the formation of $1,3,5-cyclohexatriene$ (benzene) $(D)$ as the final product.

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